![]() ![]() My other guess is perhaps you are saying its BECAUSE it is cooler that this is a problem: the molten filament hardens too quickly vs. If that isn't at all what you're saying, I apologize for misunderstanding. Remember, heat transfer is based on temperature difference, so less heat into the heat sink only happens if the heat break is actually just that much cooler. This then causes a temporary jam, which can be seen as a void in the print.Īre you trying to say that the titanium heat break is getting hotter, resulting in filament saying molten to a higher point than it otherwise would? If so, then that is not the case - higher thermal resistance means every part of the heat break is going to be cooler compared to a stainless steel one, simply because the thermal gradient is sharper - more heat is kept in the hot end and less transfers out of it. The only way the heat break could be transferring less heat into the heat sink is if it is, in fact, cooler.Īctually, I am confused by this statement:īecause of this, when the printer performs a retraction move, molten filament is being sucked up into the heat break. What this means is that if the top part of a stainless steel heat break is, say, 45☌, it will transfer exactly as much heat into the heat sink (assuming the same contact area/quality of that contact) as a titanium heat break that is also 45☌. Thermal conductivity will determine how quickly heat flows within each object, and thus how sharp a temperature gradient is developed, but it doesn't have any effect on thermal transfer between the objects. Heat transfer between two objects in contact depends on the contract area and the temperature difference, it does not depend on the thermal conductivities of the two objects. ![]() Note that less heat transfer means the heat break is cooler, not warmer. However, it also causes less heat transfer from the heat break It is a desirable characteristic, and yes, that is the purpose. ![]() This might seem like a desirable characteristic, given the purpose of a heat break is to minimize heat transfer from the hot end up into the heat sink. The low-conductivity titanium alloys have between 3-4 times more thermal resistance than stainless steel. ![]() Titanium has a much lower thermal conductivity than the steel used in the regular heat break. With chopped carbon fiber filaments it works wonders! I Ordered some Winsinn Ti heatbreaks and I have never looked back I do print at hot temperatures though and rarely ever print with PLA. Once I replaced it ( along with a PC extruder body and copper block) I have not had a issue with ABS jamming again. I have never really had a issue with my 3 printers that I have modified with a Ti heatbreak. Re: Don't buy the E3D titanium heat break So unless you NEED the titanium heat break, which is useful for printing at very hot temperatures, do yourself, and your wallet, a favor, and just get the regular stainless steel E3D heat break, or the Micro-Swiss heat break. This then causes a temporary jam, which can be seen as a void in the print. Because of this, when the printer performs a retraction move, molten filament is being sucked up into the heat break. However, it also causes less heat transfer from the heat break to the heat sink. I now wish I had never heard of this product. But after hearing about their titanium heat break, I decided to go that route instead. Initially I intended to buy a normal E3D V6 heat break, for about 1/3 the cost of this. So like many others, I decided to just replace the heat break. It is a well known issue that some printers made before a certain date have a heat break with a machining issue (a "step") that causes filament jams and poor extrusion. ![]()
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